Valid Anagram
題意:
Given two strings s and t, write a function to determine if t is an anagram of s.
For example, s = "anagram", t = "nagaram", return true. s = "rat", t = "car", return false.
Note: You may assume the string contains only lowercase alphabets.
Follow up: What if the inputs contain unicode characters? How would you adapt your solution to such case?
解題思路:
如果是使用ascii編碼,則使用一個長度為256的陣列即可。
public class Solution {
public boolean isAnagram(String s, String t) {
if (s.length() != t.length()) {
return false;
}
int[] count = new int[256];
for (int i = 0; i < s.length(); i++) {
count[s.charAt(i) - 'a']++;
count[t.charAt(i) - 'a']--;
}
for (int i = 0; i < 256; i++) {
if (count[i] != 0) {
return false;
}
}
return true;
}
}