Contains Duplicates II
題意:
Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k.
解題思路:
一樣用set,一但i大於k時,每加一個前要先刪掉一個set中最前面的元素。
public class Solution {
public boolean containsNearbyDuplicate(int[] nums, int k) {
if (nums == null || nums.length == 0 || k == 0) {
return false;
}
HashSet<Integer> set = new HashSet<Integer>();
for (int i = 0; i < nums.length; i++) {
if ( i > k) {
set.remove(nums[i - k - 1]);
}
if (!set.add(nums[i])) {
return true;
}
}
return false;
}
}